思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
2 For points outside the convex hull, an acceptable solution is to find the closest point on the surface and determine the barycentric coordinates for that point instead. ↑
，这一点在Line官方版本下载中也有详细论述
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